2^2y=1/8

Solution for 2^2y=1/8 equation:

2^2y=1/8

We move all terms to the left:

2^2y-(1/8)=0

We add all the numbers together, and all the variables

2^2y-(+1/8)=0

We get rid of parentheses

2^2y-1/8=0

We multiply all the terms by the denominator


2^2y*8-1=0

Wy multiply elements

16y^2-1=0

a = 16; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·16·(-1)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*16}=\frac{-8}{32}
=-1/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*16}=\frac{8}{32}
=1/4
$